same duplicate occurences of two times is allowed in this question, the first one had only one occurence allowed
brute force thinking and solution
there are some facts to consider
- the k will start from 2 as two are allowed
- and as two are allowed the step becomes nums[i] != nums[k-2]
pseudocode
if size of array less than 2 return size then for i=0 → n if nums[k]!=nums[i] numsk = numsi k++;